Korean research assistant

Geschlossen Veröffentlicht vor 5 Jahren Bezahlt bei Lieferung
Geschlossen Bezahlt bei Lieferung

Search for vendor according to specific criteria

Internet-Recherche Koreanisch-Übersetzer Recherche Social Networking

Projekt-ID: #17602619

Über das Projekt

15 Vorschläge Remote Projekt Aktiv vor 5 Jahren

15 Freelancer bieten im Durchschnitt $1428 für diesen Job

smtechnology

Hi, I am an experienced researcher. I will search for vendor according to specific criteria. Please tell me your criteria so I can know. Thanks SM

$1500 HKD in 3 Tagen
(111 Bewertungen)
6.4
ufoteam

Professional Korean translation/help service *If you are not satisfied with our services or feel that the translation results we provide to you are not accurate enough, we promise to provide you with a 100% refund.( Mehr

$1244 HKD in 3 Tagen
(6 Bewertungen)
4.0
Jinxuetian

Sir. Korean research assistant?? Search for vendor according to specific criteria?? DO NOT WORRY AT ALL please ..! ---------------------------------------------------- PERFECT! PERFECT! PERFECT! 101% 101% 101% Mehr

$1244 HKD in 3 Tagen
(1 Bewertung)
0.7
Mshahzadalamkhan

Hi, me shahzad, I have wrote research paper. I have experience with this types of thing (like research) and I will be very suitable for you just because of my intrest and experience research work. Relevant Skills and Mehr

$1244 HKD in 3 Tagen
(0 Bewertungen)
0.0
minieony

I would like to apply for the above position with you. I am Seung-min (Duke) Shin who is a student in the MA course ‘Poverty and Development' from the Institute of Development(University of Sussex). I have relevant exp Mehr

$2222 HKD in 3 Tagen
(0 Bewertungen)
0.0
xborders

Let me carry this assignment! I am fully experienced with the internet research. Very fast and accurate.

$1444 HKD in 3 Tagen
(0 Bewertungen)
0.0
Hazald

I know English and Korean so well and my step mother is Korean so it's my second language :) and we can negotiate the price too, I'm so willing to work

$1244 HKD in 3 Tagen
(0 Bewertungen)
0.0