CHEMISTRY HOMEWORK

Hello, I would be interested in doing this task (I think this is a repost of another similar project). I have read your assignment problems and can do it. Regards, Adem

A proposal has not yet been provided

Hi, dear contact me I will give you 100 % accurate solution. I am a chemistry expert you can trust me.

hi i am doing my PhD in chemistry.i am expert in chemistry i can help you . I will solve step by step and write with hand and send please contact me thank you

Great quality work will be provided in order to the endless solution of problem. My services can sustain your position

Hi.. I am expert in this field and will give you 100% accurate work on given time. Not let down your work in any condition. THANKS YOU...

Hello..I did an offer other advert but you cancel it..If you contact with me i can help you for this lessons..

Dear sir, i am currently a university student Studying Engineering in Bangladesh. i have completed my O level and A level under Edexcel IGCSE and GCE Edexcel which are under London curriculum and so i am well aware of excellent English. I am dedicated to provide you services at your requirement and i know that i have the ability to make you satisfied. Please do Find the Answer for the first question that you have mentioned in the pdf file. Ans1: a) Na2 CO3+ 2HCl →2NaCl+CO_2+ H_2 O b) Mole= Volume/(24000 〖ml〗^3 ) =1871/24000 =0.07795 mol =0.078 mol Mole Ratio of CO2: HCl = 1 : 2 So, the number of mole of HCl is 2 x 0.078 mol. = 0.156 mol The mole ratio of HCl : Na2 CO3 = 2 : 1 So, the number of mole of Na2 CO3 is 0.156/2 = 0.078 mol Mass= mole x Molar mass = 0.078 x [(23x2) + 12 + (16x3)] = 8.268 g = 8.27 g Percentage of Na2 CO3 is 8.27/10 x 100 % = 82.7 % Hope to hear a positive and prompt reply from your end. Thank you Regards Ashir

3 days is enough just send me the questions and ill have them done in 3 days tops. do you want them to be in my handwriting or a tex you can copy?