Php script duplicated problem

Hello, With 99% completion rate, 700 successfully completed projects, and a 5.00 reputation (maximum possible, 5.0) (Yes, not even 4.99 average rating, can be verified on my profile page !!)... you can never go wrong choosing me :) I look forward to your reply. Thanks. Kind Regards, Rajesh Soni

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i can fix the script for you. i can fix the script for you. i can fix the script for you. i can fix the script for you. i can fix the script for you.

Hi, I can fix that problem easily. I have fixed same problem like that before. Ready to work it now. I need ftp access to work this task. Can you provide? Regards,

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Hi, I can start right now. .

yes brother i will fix your php script with quality work and as soon as possible thanks Hope a good news from your side.

Hi this is miral, an expert in php. I have 2 yrs of experience and i can guerantee you to fix this bug in couple of hours. Thanks.

Hello I am PHP developer since last 3 year i have work on the SAAS base project i have work. i believe to provide quality of the work. If you want then choose me and give some work i will prove my knowledge and also provide quality of work. Give me these chance to prove my self i have good knowledge of Zend ,CodeIgniter , My sql(Store procedure, Trigger) key strength. My skpe Id rotz.d

I can do the work, I have SEVERAL years of experience in this domainesi you can give me more detail so that I can give you an exact figure given

hi sen me the detail so i will show you tomorrow when the issue done , i have rate very low , because this is not any typical task may be code is typical but i will do that at same rate Thanks Arsalan

dear madam/sir ; you can send me the script , i can fix asap , hopefully today. waiting for your script. best regrads

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easy job. i can deliver it quickly, while we are chatting in skype. you can check it online via my server.

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I think you can manage to do it by yourself: 1) pure SQL solution: - set unique key on email; - set unique key on username; - execute the following query (whatever method you use for MySQL): 'INSERT IGNORE INTO table_name(username, email, ...) VALUES("'.$username.'", "'.$email.'", ...);' the escaping of variables depends on which method you use for querying database (PDO, ORMs, etc); 2) PHP method - retrieve from database the row which has entered username or email: 'SELECT count(*) FROM table_name WHERE username="'.$username.'";' - check the value of result: if 0 than you can insert the new one; if >0 than do nothing; hope it helps

Hello, Your problem is easily solved with sql. What kind of database are you using? Please contact me for more info. Best regards, Boian Ivanov.